Solve 1-7/8-(1/2-2)^3+(-2/3)^-3=

$$1 - \frac { 7 } { 8 } - ( \frac { 1 } { 2 } - 2 ) ^ { 3 } + ( - \frac { 2 } { 3 } ) ^ { - 3 } =$$

Evaluate

$$\frac{1}{8}=0.125$$

Solution Steps

Subtract \frac{7}{8} from 1 to get \frac{1}{8}.

$$\frac{1}{8}-\left(\frac{1}{2}-2\right)^{3}+\left(-\frac{2}{3}\right)^{-3}$$

Subtract 2 from \frac{1}{2} to get -\frac{3}{2}.

$$\frac{1}{8}-\left(-\frac{3}{2}\right)^{3}+\left(-\frac{2}{3}\right)^{-3}$$

Calculate -\frac{3}{2} to the power of 3 and get -\frac{27}{8}.

$$\frac{1}{8}-\left(-\frac{27}{8}\right)+\left(-\frac{2}{3}\right)^{-3}$$

The opposite of -\frac{27}{8} is \frac{27}{8}.

$$\frac{1}{8}+\frac{27}{8}+\left(-\frac{2}{3}\right)^{-3}$$

Add \frac{1}{8} and \frac{27}{8} to get \frac{7}{2}.

$$\frac{7}{2}+\left(-\frac{2}{3}\right)^{-3}$$

Calculate -\frac{2}{3} to the power of -3 and get -\frac{27}{8}.

$$\frac{7}{2}-\frac{27}{8}$$

Subtract \frac{27}{8} from \frac{7}{2} to get \frac{1}{8}.

$$\frac{1}{8}$$

Factor

$$\frac{1}{2 ^ {3}} = 0.125$$