Solve 1-7/5=7/7-7/5=7/2

$$1 - \frac { 7 } { 5 } = \frac { 7 } { 7 } - \frac { 7 } { 5 } = \frac { 7 } { 2 }$$

Verify

Solution Steps

Divide 7 by 7 to get 1.

$$1-\frac{7}{5}=1-\frac{7}{5}\text{ and }\frac{7}{7}-\frac{7}{5}=\frac{7}{2}$$

Divide 7 by 7 to get 1.

$$1-\frac{7}{5}=1-\frac{7}{5}\text{ and }1-\frac{7}{5}=\frac{7}{2}$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{5}{5}-\frac{7}{5}=1-\frac{7}{5}\text{ and }1-\frac{7}{5}=\frac{7}{2}$$

Since \frac{5}{5} and \frac{7}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-7}{5}=1-\frac{7}{5}\text{ and }1-\frac{7}{5}=\frac{7}{2}$$

Subtract 7 from 5 to get -2.

$$-\frac{2}{5}=1-\frac{7}{5}\text{ and }1-\frac{7}{5}=\frac{7}{2}$$

Convert 1 to fraction \frac{5}{5}.

$$-\frac{2}{5}=\frac{5}{5}-\frac{7}{5}\text{ and }1-\frac{7}{5}=\frac{7}{2}$$

Since \frac{5}{5} and \frac{7}{5} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{2}{5}=\frac{5-7}{5}\text{ and }1-\frac{7}{5}=\frac{7}{2}$$

Subtract 7 from 5 to get -2.

$$-\frac{2}{5}=-\frac{2}{5}\text{ and }1-\frac{7}{5}=\frac{7}{2}$$

Compare -\frac{2}{5} and -\frac{2}{5}.

$$\text{true}\text{ and }1-\frac{7}{5}=\frac{7}{2}$$

Convert 1 to fraction \frac{5}{5}.

$$\text{true}\text{ and }\frac{5}{5}-\frac{7}{5}=\frac{7}{2}$$

Since \frac{5}{5} and \frac{7}{5} have the same denominator, subtract them by subtracting their numerators.

$$\text{true}\text{ and }\frac{5-7}{5}=\frac{7}{2}$$

Subtract 7 from 5 to get -2.

$$\text{true}\text{ and }-\frac{2}{5}=\frac{7}{2}$$

Least common multiple of 5 and 2 is 10. Convert -\frac{2}{5} and \frac{7}{2} to fractions with denominator 10.

$$\text{true}\text{ and }-\frac{4}{10}=\frac{35}{10}$$

Compare -\frac{4}{10} and \frac{35}{10}.

$$\text{true}\text{ and }\text{false}$$

The conjunction of \text{true} and \text{false} is \text{false}.

$$\text{false}$$