Solve 1-6*30:5/9^3-9

$$1 - \frac { 6 \times 30 : 5 } { 9 ^ { 3 } - 9 }$$

Evaluate

$$\frac{19}{20}=0.95$$

Solution Steps

Multiply 6 and 30 to get 180.

$$1-\frac{\frac{180}{5}}{9^{3}-9}$$

Divide 180 by 5 to get 36.

$$1-\frac{36}{9^{3}-9}$$

Calculate 9 to the power of 3 and get 729.

$$1-\frac{36}{729-9}$$

Subtract 9 from 729 to get 720.

$$1-\frac{36}{720}$$

Reduce the fraction \frac{36}{720} to lowest terms by extracting and canceling out 36.

$$1-\frac{1}{20}$$

Convert 1 to fraction \frac{20}{20}.

$$\frac{20}{20}-\frac{1}{20}$$

Since \frac{20}{20} and \frac{1}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20-1}{20}$$

Subtract 1 from 20 to get 19.

$$\frac{19}{20}$$

Factor

$$\frac{19}{2 ^ {2} \cdot 5} = 0.95$$