Solve 1-5-2-3/2+7/12-(-7/2)+-4/5=

$$1 - \frac { 5 - 2 - 3 } { 2 } + \frac { 7 } { 12 } - ( - \frac { 7 } { 2 } ) + \frac { - 4 } { 5 } =$$

Evaluate

$$\frac{257}{60}\approx 4.283333333$$

Solution Steps

Subtract 2 from 5 to get 3.

$$1-\frac{3-3}{2}+\frac{7}{12}-\left(-\frac{7}{2}\right)+\frac{-4}{5}$$

Subtract 3 from 3 to get 0.

$$1-\frac{0}{2}+\frac{7}{12}-\left(-\frac{7}{2}\right)+\frac{-4}{5}$$

Zero divided by any non-zero number gives zero.

$$1+0+\frac{7}{12}-\left(-\frac{7}{2}\right)+\frac{-4}{5}$$

Add 1 and 0 to get 1.

$$1+\frac{7}{12}-\left(-\frac{7}{2}\right)+\frac{-4}{5}$$

Convert 1 to fraction \frac{12}{12}.

$$\frac{12}{12}+\frac{7}{12}-\left(-\frac{7}{2}\right)+\frac{-4}{5}$$

Since \frac{12}{12} and \frac{7}{12} have the same denominator, add them by adding their numerators.

$$\frac{12+7}{12}-\left(-\frac{7}{2}\right)+\frac{-4}{5}$$

Add 12 and 7 to get 19.

$$\frac{19}{12}-\left(-\frac{7}{2}\right)+\frac{-4}{5}$$

The opposite of -\frac{7}{2} is \frac{7}{2}.

$$\frac{19}{12}+\frac{7}{2}+\frac{-4}{5}$$

Least common multiple of 12 and 2 is 12. Convert \frac{19}{12} and \frac{7}{2} to fractions with denominator 12.

$$\frac{19}{12}+\frac{42}{12}+\frac{-4}{5}$$

Since \frac{19}{12} and \frac{42}{12} have the same denominator, add them by adding their numerators.

$$\frac{19+42}{12}+\frac{-4}{5}$$

Add 19 and 42 to get 61.

$$\frac{61}{12}+\frac{-4}{5}$$

Fraction \frac{-4}{5} can be rewritten as -\frac{4}{5} by extracting the negative sign.

$$\frac{61}{12}-\frac{4}{5}$$

Least common multiple of 12 and 5 is 60. Convert \frac{61}{12} and \frac{4}{5} to fractions with denominator 60.

$$\frac{305}{60}-\frac{48}{60}$$

Since \frac{305}{60} and \frac{48}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{305-48}{60}$$

Subtract 48 from 305 to get 257.

$$\frac{257}{60}$$

Factor

$$\frac{257}{2 ^ {2} \cdot 3 \cdot 5} = 4\frac{17}{60} = 4.283333333333333$$