Solve 1-3/5=quad14/15-4/15=10/15

$$1 - \frac { 3 } { 5 } = \quad \frac { 14 } { 15 } - \frac { 4 } { 15 } = \frac { 10 } { 15 }$$

Verify

Solution Steps

Convert 1 to fraction \frac{5}{5}.

$$\frac{5}{5}-\frac{3}{5}=\frac{14}{15}-\frac{4}{15}\text{ and }\frac{14}{15}-\frac{4}{15}=\frac{10}{15}$$

Since \frac{5}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-3}{5}=\frac{14}{15}-\frac{4}{15}\text{ and }\frac{14}{15}-\frac{4}{15}=\frac{10}{15}$$

Subtract 3 from 5 to get 2.

$$\frac{2}{5}=\frac{14}{15}-\frac{4}{15}\text{ and }\frac{14}{15}-\frac{4}{15}=\frac{10}{15}$$

Since \frac{14}{15} and \frac{4}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2}{5}=\frac{14-4}{15}\text{ and }\frac{14}{15}-\frac{4}{15}=\frac{10}{15}$$

Subtract 4 from 14 to get 10.

$$\frac{2}{5}=\frac{10}{15}\text{ and }\frac{14}{15}-\frac{4}{15}=\frac{10}{15}$$

Reduce the fraction \frac{10}{15} to lowest terms by extracting and canceling out 5.

$$\frac{2}{5}=\frac{2}{3}\text{ and }\frac{14}{15}-\frac{4}{15}=\frac{10}{15}$$

Least common multiple of 5 and 3 is 15. Convert \frac{2}{5} and \frac{2}{3} to fractions with denominator 15.

$$\frac{6}{15}=\frac{10}{15}\text{ and }\frac{14}{15}-\frac{4}{15}=\frac{10}{15}$$

Compare \frac{6}{15} and \frac{10}{15}.

$$\text{false}\text{ and }\frac{14}{15}-\frac{4}{15}=\frac{10}{15}$$

Since \frac{14}{15} and \frac{4}{15} have the same denominator, subtract them by subtracting their numerators.

$$\text{false}\text{ and }\frac{14-4}{15}=\frac{10}{15}$$

Subtract 4 from 14 to get 10.

$$\text{false}\text{ and }\frac{10}{15}=\frac{10}{15}$$

Reduce the fraction \frac{10}{15} to lowest terms by extracting and canceling out 5.

$$\text{false}\text{ and }\frac{2}{3}=\frac{10}{15}$$

Reduce the fraction \frac{10}{15} to lowest terms by extracting and canceling out 5.

$$\text{false}\text{ and }\frac{2}{3}=\frac{2}{3}$$

Compare \frac{2}{3} and \frac{2}{3}.

$$\text{false}\text{ and }\text{true}$$

The conjunction of \text{false} and \text{true} is \text{false}.

$$\text{false}$$