Solve 1-1/3*(1/2-1/6)

$$1 - \frac { 1 } { 3 } \cdot ( \frac { 1 } { 2 } - \frac { 1 } { 6 } )$$

Evaluate

$$\frac{8}{9}\approx 0.888888889$$

Solution Steps

Least common multiple of 2 and 6 is 6. Convert \frac{1}{2} and \frac{1}{6} to fractions with denominator 6.

$$1-\frac{1}{3}\left(\frac{3}{6}-\frac{1}{6}\right)$$

Since \frac{3}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$1-\frac{1}{3}\times \frac{3-1}{6}$$

Subtract 1 from 3 to get 2.

$$1-\frac{1}{3}\times \frac{2}{6}$$

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$1-\frac{1}{3}\times \frac{1}{3}$$

Multiply \frac{1}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$1-\frac{1\times 1}{3\times 3}$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 3}.

$$1-\frac{1}{9}$$

Convert 1 to fraction \frac{9}{9}.

$$\frac{9}{9}-\frac{1}{9}$$

Since \frac{9}{9} and \frac{1}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-1}{9}$$

Subtract 1 from 9 to get 8.

$$\frac{8}{9}$$

Factor

$$\frac{2 ^ {3}}{3 ^ {2}} = 0.8888888888888888$$