Solve 1-1/3+1/4+1/6=

$$1 - \frac { 1 } { 3 } + \frac { 1 } { 4 } + \frac { 1 } { 6 } =$$

Evaluate

$$\frac{13}{12}\approx 1.083333333$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$\frac{3}{3}-\frac{1}{3}+\frac{1}{4}+\frac{1}{6}$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-1}{3}+\frac{1}{4}+\frac{1}{6}$$

Subtract 1 from 3 to get 2.

$$\frac{2}{3}+\frac{1}{4}+\frac{1}{6}$$

Least common multiple of 3 and 4 is 12. Convert \frac{2}{3} and \frac{1}{4} to fractions with denominator 12.

$$\frac{8}{12}+\frac{3}{12}+\frac{1}{6}$$

Since \frac{8}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{8+3}{12}+\frac{1}{6}$$

Add 8 and 3 to get 11.

$$\frac{11}{12}+\frac{1}{6}$$

Least common multiple of 12 and 6 is 12. Convert \frac{11}{12} and \frac{1}{6} to fractions with denominator 12.

$$\frac{11}{12}+\frac{2}{12}$$

Since \frac{11}{12} and \frac{2}{12} have the same denominator, add them by adding their numerators.

$$\frac{11+2}{12}$$

Add 11 and 2 to get 13.

$$\frac{13}{12}$$

Factor

$$\frac{13}{2 ^ {2} \cdot 3} = 1\frac{1}{12} = 1.0833333333333333$$