Solve 1-[6*(2+3)-(4+1)*2]*2

$$1 - [ 6 \cdot ( 2 + 3 ) - ( 4 + 1 ) \cdot 2 ] \cdot 2$$

Evaluate

$$-39$$

Solution Steps

Add 2 and 3 to get 5.

$$1-\left(6\times 5-\left(4+1\right)\times 2\right)\times 2$$

Multiply 6 and 5 to get 30.

$$1-\left(30-\left(4+1\right)\times 2\right)\times 2$$

Add 4 and 1 to get 5.

$$1-\left(30-5\times 2\right)\times 2$$

Multiply 5 and 2 to get 10.

$$1-\left(30-10\right)\times 2$$

Subtract 10 from 30 to get 20.

$$1-20\times 2$$

Multiply 20 and 2 to get 40.

$$1-40$$

Subtract 40 from 1 to get -39.

$$-39$$

Factor

$$-39$$