Solve 1-[(-3*6)+1]-[4*(6-3+1)-2]=

$$1 - [ ( - 3 \cdot 6 ) + 1 ] - [ 4 \cdot ( 6 - 3 + 1 ) - 2 ] =$$

Evaluate

$$4$$

Solution Steps

Multiply -3 and 6 to get -18.

$$1-\left(-18+1\right)-\left(4\left(6-3+1\right)-2\right)$$

Add -18 and 1 to get -17.

$$1-\left(-17\right)-\left(4\left(6-3+1\right)-2\right)$$

The opposite of -17 is 17.

$$1+17-\left(4\left(6-3+1\right)-2\right)$$

Add 1 and 17 to get 18.

$$18-\left(4\left(6-3+1\right)-2\right)$$

Subtract 3 from 6 to get 3.

$$18-\left(4\left(3+1\right)-2\right)$$

Add 3 and 1 to get 4.

$$18-\left(4\times 4-2\right)$$

Multiply 4 and 4 to get 16.

$$18-\left(16-2\right)$$

Subtract 2 from 16 to get 14.

$$18-14$$

Subtract 14 from 18 to get 4.

$$4$$

Factor

$$2^{2}$$