Solve 1(21/4+38/7)=7

$$1 ( 2 \frac { 1 } { 4 } + 3 \frac { 8 } { 7 } ) = 7$$

Verify

Solution Steps

Multiply both sides of the equation by 28, the least common multiple of 4,7.

$$28\left(\frac{2\times 4+1}{4}+\frac{3\times 7+8}{7}\right)=196$$

Multiply 2 and 4 to get 8.

$$28\left(\frac{8+1}{4}+\frac{3\times 7+8}{7}\right)=196$$

Add 8 and 1 to get 9.

$$28\left(\frac{9}{4}+\frac{3\times 7+8}{7}\right)=196$$

Multiply 3 and 7 to get 21.

$$28\left(\frac{9}{4}+\frac{21+8}{7}\right)=196$$

Add 21 and 8 to get 29.

$$28\left(\frac{9}{4}+\frac{29}{7}\right)=196$$

Least common multiple of 4 and 7 is 28. Convert \frac{9}{4} and \frac{29}{7} to fractions with denominator 28.

$$28\left(\frac{63}{28}+\frac{116}{28}\right)=196$$

Since \frac{63}{28} and \frac{116}{28} have the same denominator, add them by adding their numerators.

$$28\times \frac{63+116}{28}=196$$

Add 63 and 116 to get 179.

$$28\times \frac{179}{28}=196$$

Cancel out 28 and 28.

$$179=196$$

Compare 179 and 196.

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