Solve 1(-8a^4b^2)(-4a^2b^2)

$$1 ( - 8 a ^ { 4 } b ^ { 2 } ) ( - 4 a ^ { 2 } b ^ { 2 } )$$

Evaluate

$$32b^{4}a^{6}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$\left(-8\right)^{1}a^{4}b^{2}\left(-4\right)^{1}a^{2}b^{2}$$

Use the Commutative Property of Multiplication.

$$\left(-8\right)^{1}\left(-4\right)^{1}a^{4}a^{2}b^{2}b^{2}$$

To multiply powers of the same base, add their exponents.

$$\left(-8\right)^{1}\left(-4\right)^{1}a^{4+2}b^{2+2}$$

Add the exponents 4 and 2.

$$\left(-8\right)^{1}\left(-4\right)^{1}a^{6}b^{2+2}$$

Add the exponents 2 and 2.

$$\left(-8\right)^{1}\left(-4\right)^{1}a^{6}b^{4}$$

Multiply -8 times -4.

$$32a^{6}b^{4}$$

Differentiate w.r.t. a

$$192b^{4}a^{5}$$