Solve 1(-7/6a^3b)*6/5abc

$$1 ( - \frac { 7 } { 6 } a ^ { 3 } b ) \cdot \frac { 6 } { 5 } a b c$$

Evaluate

$$-\frac{7cb^{2}a^{4}}{5}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$1\left(-\frac{7}{6}\right)a^{4}b\times \frac{6}{5}bc$$

Multiply b and b to get b^{2}.

$$1\left(-\frac{7}{6}\right)a^{4}b^{2}\times \frac{6}{5}c$$

Multiply 1 and -\frac{7}{6} to get -\frac{7}{6}.

$$-\frac{7}{6}a^{4}b^{2}\times \frac{6}{5}c$$

Multiply -\frac{7}{6} and \frac{6}{5} to get -\frac{7}{5}.

$$-\frac{7}{5}a^{4}b^{2}c$$

Differentiate w.r.t. c

$$-\frac{7b^{2}a^{4}}{5}$$