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\left(\sqrt{2}+\sqrt{3}\right)\left(\sqrt{3}-\sqrt{2}\right)
Use the distributive property to multiply 1 by \sqrt{2}+\sqrt{3}.
\left(\sqrt{3}\right)^{2}-\left(\sqrt{2}\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
3-\left(\sqrt{2}\right)^{2}
The square of \sqrt{3} is 3.
3-2
The square of \sqrt{2} is 2.
1
Subtract 2 from 3 to get 1.