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\frac{\left(1\times 8+2\right)\times 4}{8\left(1\times 4+3\right)}
Divide \frac{1\times 8+2}{8} by \frac{1\times 4+3}{4} by multiplying \frac{1\times 8+2}{8} by the reciprocal of \frac{1\times 4+3}{4}.
\frac{2+8}{2\left(3+4\right)}
Cancel out 4 in both numerator and denominator.
\frac{10}{2\left(3+4\right)}
Add 2 and 8 to get 10.
\frac{10}{2\times 7}
Add 3 and 4 to get 7.
\frac{10}{14}
Multiply 2 and 7 to get 14.
\frac{5}{7}
Reduce the fraction \frac{10}{14} to lowest terms by extracting and canceling out 2.