Solve 11/40+23/20+33/8+49/20=frac{13}{4}

$$1 \frac{ 1 }{ 40 } +2 \frac{ 3 }{ 20 } +3 \frac{ 3 }{ 8 } +4 \frac{ 9 }{ 20 } = \frac{ 13 }{ 4 }$$

Verify

Solution Steps

Multiply both sides of the equation by 40, the least common multiple of 40,20,8,4.

$$1\times 40+1+2\left(2\times 20+3\right)+5\left(3\times 8+3\right)+2\left(4\times 20+9\right)=130$$

Multiply 1 and 40 to get 40.

$$40+1+2\left(2\times 20+3\right)+5\left(3\times 8+3\right)+2\left(4\times 20+9\right)=130$$

Add 40 and 1 to get 41.

$$41+2\left(2\times 20+3\right)+5\left(3\times 8+3\right)+2\left(4\times 20+9\right)=130$$

Multiply 2 and 20 to get 40.

$$41+2\left(40+3\right)+5\left(3\times 8+3\right)+2\left(4\times 20+9\right)=130$$

Add 40 and 3 to get 43.

$$41+2\times 43+5\left(3\times 8+3\right)+2\left(4\times 20+9\right)=130$$

Multiply 2 and 43 to get 86.

$$41+86+5\left(3\times 8+3\right)+2\left(4\times 20+9\right)=130$$

Add 41 and 86 to get 127.

$$127+5\left(3\times 8+3\right)+2\left(4\times 20+9\right)=130$$

Multiply 3 and 8 to get 24.

$$127+5\left(24+3\right)+2\left(4\times 20+9\right)=130$$

Add 24 and 3 to get 27.

$$127+5\times 27+2\left(4\times 20+9\right)=130$$

Multiply 5 and 27 to get 135.

$$127+135+2\left(4\times 20+9\right)=130$$

Add 127 and 135 to get 262.

$$262+2\left(4\times 20+9\right)=130$$

Multiply 4 and 20 to get 80.

$$262+2\left(80+9\right)=130$$

Add 80 and 9 to get 89.

$$262+2\times 89=130$$

Multiply 2 and 89 to get 178.

$$262+178=130$$

Add 262 and 178 to get 440.

$$440=130$$

Compare 440 and 130.

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