Solve 17/9div22/3

$$1 \frac { 7 } { 9 } \div 2 \frac { 2 } { 3 }$$

Evaluate

$$\frac{2}{3}\approx 0.666666667$$

Solution Steps

Divide \frac{1\times 9+7}{9} by \frac{2\times 3+2}{3} by multiplying \frac{1\times 9+7}{9} by the reciprocal of \frac{2\times 3+2}{3}.

$$\frac{\left(1\times 9+7\right)\times 3}{9\left(2\times 3+2\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{7+9}{3\left(2+2\times 3\right)}$$

Add 7 and 9 to get 16.

$$\frac{16}{3\left(2+2\times 3\right)}$$

Multiply 2 and 3 to get 6.

$$\frac{16}{3\left(2+6\right)}$$

Add 2 and 6 to get 8.

$$\frac{16}{3\times 8}$$

Multiply 3 and 8 to get 24.

$$\frac{16}{24}$$

Reduce the fraction \frac{16}{24} to lowest terms by extracting and canceling out 8.

$$\frac{2}{3}$$

Factor

$$\frac{2}{3} = 0.6666666666666666$$