Solve 16/8+311/10=

$$1 \frac { 6 } { 8 } + 3 \frac { 11 } { 10 } =$$

Evaluate

$$\frac{117}{20}=5.85$$

Solution Steps

Multiply 1 and 8 to get 8.

$$\frac{8+6}{8}+\frac{3\times 10+11}{10}$$

Add 8 and 6 to get 14.

$$\frac{14}{8}+\frac{3\times 10+11}{10}$$

Reduce the fraction \frac{14}{8} to lowest terms by extracting and canceling out 2.

$$\frac{7}{4}+\frac{3\times 10+11}{10}$$

Multiply 3 and 10 to get 30.

$$\frac{7}{4}+\frac{30+11}{10}$$

Add 30 and 11 to get 41.

$$\frac{7}{4}+\frac{41}{10}$$

Least common multiple of 4 and 10 is 20. Convert \frac{7}{4} and \frac{41}{10} to fractions with denominator 20.

$$\frac{35}{20}+\frac{82}{20}$$

Since \frac{35}{20} and \frac{82}{20} have the same denominator, add them by adding their numerators.

$$\frac{35+82}{20}$$

Add 35 and 82 to get 117.

$$\frac{117}{20}$$

Factor

$$\frac{3 ^ {2} \cdot 13}{2 ^ {2} \cdot 5} = 5\frac{17}{20} = 5.85$$