Solve 13/8+31/2-21/4=

$$1 \frac { 3 } { 8 } + 3 \frac { 1 } { 2 } - 2 \frac { 1 } { 4 } =$$

Evaluate

$$\frac{21}{8}=2.625$$

Solution Steps

Multiply 1 and 8 to get 8.

$$\frac{8+3}{8}+\frac{3\times 2+1}{2}-\frac{2\times 4+1}{4}$$

Add 8 and 3 to get 11.

$$\frac{11}{8}+\frac{3\times 2+1}{2}-\frac{2\times 4+1}{4}$$

Multiply 3 and 2 to get 6.

$$\frac{11}{8}+\frac{6+1}{2}-\frac{2\times 4+1}{4}$$

Add 6 and 1 to get 7.

$$\frac{11}{8}+\frac{7}{2}-\frac{2\times 4+1}{4}$$

Least common multiple of 8 and 2 is 8. Convert \frac{11}{8} and \frac{7}{2} to fractions with denominator 8.

$$\frac{11}{8}+\frac{28}{8}-\frac{2\times 4+1}{4}$$

Since \frac{11}{8} and \frac{28}{8} have the same denominator, add them by adding their numerators.

$$\frac{11+28}{8}-\frac{2\times 4+1}{4}$$

Add 11 and 28 to get 39.

$$\frac{39}{8}-\frac{2\times 4+1}{4}$$

Multiply 2 and 4 to get 8.

$$\frac{39}{8}-\frac{8+1}{4}$$

Add 8 and 1 to get 9.

$$\frac{39}{8}-\frac{9}{4}$$

Least common multiple of 8 and 4 is 8. Convert \frac{39}{8} and \frac{9}{4} to fractions with denominator 8.

$$\frac{39}{8}-\frac{18}{8}$$

Since \frac{39}{8} and \frac{18}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{39-18}{8}$$

Subtract 18 from 39 to get 21.

$$\frac{21}{8}$$

Factor

$$\frac{3 \cdot 7}{2 ^ {3}} = 2\frac{5}{8} = 2.625$$