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Solve for L
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\frac{5+3}{5}L-\frac{c}{5}=d
Multiply 1 and 5 to get 5.
\frac{8}{5}L-\frac{c}{5}=d
Add 5 and 3 to get 8.
\frac{8}{5}L=d+\frac{c}{5}
Add \frac{c}{5} to both sides.
8L=5d+c
Multiply both sides of the equation by 5.
8L=c+5d
The equation is in standard form.
\frac{8L}{8}=\frac{c+5d}{8}
Divide both sides by 8.
L=\frac{c+5d}{8}
Dividing by 8 undoes the multiplication by 8.
\frac{5+3}{5}L-\frac{c}{5}=d
Multiply 1 and 5 to get 5.
\frac{8}{5}L-\frac{c}{5}=d
Add 5 and 3 to get 8.
-\frac{c}{5}=d-\frac{8}{5}L
Subtract \frac{8}{5}L from both sides.
-c=5d-8L
Multiply both sides of the equation by 5.
\frac{-c}{-1}=\frac{5d-8L}{-1}
Divide both sides by -1.
c=\frac{5d-8L}{-1}
Dividing by -1 undoes the multiplication by -1.
c=8L-5d
Divide -8L+5d by -1.