Evaluate
\frac{12}{41}\approx 0.292682927
Factor
\frac{2 ^ {2} \cdot 3}{41} = 0.2926829268292683
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\frac{\left(1\times 5+3\right)\times 15}{5\left(5\times 15+7\right)}
Divide \frac{1\times 5+3}{5} by \frac{5\times 15+7}{15} by multiplying \frac{1\times 5+3}{5} by the reciprocal of \frac{5\times 15+7}{15}.
\frac{3\left(3+5\right)}{7+5\times 15}
Cancel out 5 in both numerator and denominator.
\frac{3\times 8}{7+5\times 15}
Add 3 and 5 to get 8.
\frac{24}{7+5\times 15}
Multiply 3 and 8 to get 24.
\frac{24}{7+75}
Multiply 5 and 15 to get 75.
\frac{24}{82}
Add 7 and 75 to get 82.
\frac{12}{41}
Reduce the fraction \frac{24}{82} to lowest terms by extracting and canceling out 2.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}