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\frac{\left(1\times 5+3\right)\times 3}{5\left(3\times 3+1\right)}
Divide \frac{1\times 5+3}{5} by \frac{3\times 3+1}{3} by multiplying \frac{1\times 5+3}{5} by the reciprocal of \frac{3\times 3+1}{3}.
\frac{\left(5+3\right)\times 3}{5\left(3\times 3+1\right)}
Multiply 1 and 5 to get 5.
\frac{8\times 3}{5\left(3\times 3+1\right)}
Add 5 and 3 to get 8.
\frac{24}{5\left(3\times 3+1\right)}
Multiply 8 and 3 to get 24.
\frac{24}{5\left(9+1\right)}
Multiply 3 and 3 to get 9.
\frac{24}{5\times 10}
Add 9 and 1 to get 10.
\frac{24}{50}
Multiply 5 and 10 to get 50.
\frac{12}{25}
Reduce the fraction \frac{24}{50} to lowest terms by extracting and canceling out 2.