Solve 13/4*3/5div11/2

$$1 \frac { 3 } { 4 } \times \frac { 3 } { 5 } \div 1 \frac { 1 } { 2 }$$

Evaluate

$$\frac{7}{10}=0.7$$

Solution Steps

Multiply 1 and 4 to get 4.

$$\frac{\frac{4+3}{4}\times \frac{3}{5}}{\frac{1\times 2+1}{2}}$$

Add 4 and 3 to get 7.

$$\frac{\frac{7}{4}\times \frac{3}{5}}{\frac{1\times 2+1}{2}}$$

Multiply \frac{7}{4} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{7\times 3}{4\times 5}}{\frac{1\times 2+1}{2}}$$

Do the multiplications in the fraction \frac{7\times 3}{4\times 5}.

$$\frac{\frac{21}{20}}{\frac{1\times 2+1}{2}}$$

Multiply 1 and 2 to get 2.

$$\frac{\frac{21}{20}}{\frac{2+1}{2}}$$

Add 2 and 1 to get 3.

$$\frac{\frac{21}{20}}{\frac{3}{2}}$$

Divide \frac{21}{20} by \frac{3}{2} by multiplying \frac{21}{20} by the reciprocal of \frac{3}{2}.

$$\frac{21}{20}\times \frac{2}{3}$$

Multiply \frac{21}{20} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{21\times 2}{20\times 3}$$

Do the multiplications in the fraction \frac{21\times 2}{20\times 3}.

$$\frac{42}{60}$$

Reduce the fraction \frac{42}{60} to lowest terms by extracting and canceling out 6.

$$\frac{7}{10}$$

Factor

$$\frac{7}{2 \cdot 5} = 0.7$$