Solve 13/4div(11/4-11/2)

$$1 \frac { 3 } { 4 } \div ( 1 \frac { 1 } { 4 } - 1 \frac { 1 } { 2 } )$$

Evaluate

$$-7$$

Solution Steps

Multiply 1 and 4 to get 4.

$$\frac{\frac{4+3}{4}}{\frac{1\times 4+1}{4}-\frac{1\times 2+1}{2}}$$

Add 4 and 3 to get 7.

$$\frac{\frac{7}{4}}{\frac{1\times 4+1}{4}-\frac{1\times 2+1}{2}}$$

Multiply 1 and 4 to get 4.

$$\frac{\frac{7}{4}}{\frac{4+1}{4}-\frac{1\times 2+1}{2}}$$

Add 4 and 1 to get 5.

$$\frac{\frac{7}{4}}{\frac{5}{4}-\frac{1\times 2+1}{2}}$$

Multiply 1 and 2 to get 2.

$$\frac{\frac{7}{4}}{\frac{5}{4}-\frac{2+1}{2}}$$

Add 2 and 1 to get 3.

$$\frac{\frac{7}{4}}{\frac{5}{4}-\frac{3}{2}}$$

Least common multiple of 4 and 2 is 4. Convert \frac{5}{4} and \frac{3}{2} to fractions with denominator 4.

$$\frac{\frac{7}{4}}{\frac{5}{4}-\frac{6}{4}}$$

Since \frac{5}{4} and \frac{6}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{7}{4}}{\frac{5-6}{4}}$$

Subtract 6 from 5 to get -1.

$$\frac{\frac{7}{4}}{-\frac{1}{4}}$$

Divide \frac{7}{4} by -\frac{1}{4} by multiplying \frac{7}{4} by the reciprocal of -\frac{1}{4}.

$$\frac{7}{4}\left(-4\right)$$

Express \frac{7}{4}\left(-4\right) as a single fraction.

$$\frac{7\left(-4\right)}{4}$$

Multiply 7 and -4 to get -28.

$$\frac{-28}{4}$$

Divide -28 by 4 to get -7.

$$-7$$

Factor

$$-7$$