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\frac{\left(1\times 4+3\right)\times 4}{4\times 14}
Divide \frac{1\times 4+3}{4} by \frac{14}{4} by multiplying \frac{1\times 4+3}{4} by the reciprocal of \frac{14}{4}.
\frac{3+4}{14}
Cancel out 4 in both numerator and denominator.
\frac{7}{14}
Add 3 and 4 to get 7.
\frac{1}{2}
Reduce the fraction \frac{7}{14} to lowest terms by extracting and canceling out 7.