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\frac{\left(1\times 4+3\right)\times 4}{4}
Divide \frac{1\times 4+3}{4} by \frac{1}{4} by multiplying \frac{1\times 4+3}{4} by the reciprocal of \frac{1}{4}.
4+3
Cancel out 4 and 4.
7
Add 4 and 3 to get 7.