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3\left(1\times 4+3\right)+12z=4\left(2\times 3+2\right)
Multiply both sides of the equation by 12, the least common multiple of 4,3.
3\left(4+3\right)+12z=4\left(2\times 3+2\right)
Multiply 1 and 4 to get 4.
3\times 7+12z=4\left(2\times 3+2\right)
Add 4 and 3 to get 7.
21+12z=4\left(2\times 3+2\right)
Multiply 3 and 7 to get 21.
21+12z=4\left(6+2\right)
Multiply 2 and 3 to get 6.
21+12z=4\times 8
Add 6 and 2 to get 8.
21+12z=32
Multiply 4 and 8 to get 32.
12z=32-21
Subtract 21 from both sides.
12z=11
Subtract 21 from 32 to get 11.
z=\frac{11}{12}
Divide both sides by 12.