Solve 13/4+212/8=

$$1 \frac { 3 } { 4 } + 2 \frac { 12 } { 8 } =$$

Evaluate

$$\frac{21}{4}=5.25$$

Solution Steps

Multiply 1 and 4 to get 4.

$$\frac{4+3}{4}+\frac{2\times 8+12}{8}$$

Add 4 and 3 to get 7.

$$\frac{7}{4}+\frac{2\times 8+12}{8}$$

Multiply 2 and 8 to get 16.

$$\frac{7}{4}+\frac{16+12}{8}$$

Add 16 and 12 to get 28.

$$\frac{7}{4}+\frac{28}{8}$$

Reduce the fraction \frac{28}{8} to lowest terms by extracting and canceling out 4.

$$\frac{7}{4}+\frac{7}{2}$$

Least common multiple of 4 and 2 is 4. Convert \frac{7}{4} and \frac{7}{2} to fractions with denominator 4.

$$\frac{7}{4}+\frac{14}{4}$$

Since \frac{7}{4} and \frac{14}{4} have the same denominator, add them by adding their numerators.

$$\frac{7+14}{4}$$

Add 7 and 14 to get 21.

$$\frac{21}{4}$$

Factor

$$\frac{3 \cdot 7}{2 ^ {2}} = 5\frac{1}{4} = 5.25$$