Solve 13/4+1/6-1/3

$$1 \frac { 3 } { 4 } + \frac { 1 } { 6 } - \frac { 1 } { 3 }$$

Evaluate

$$\frac{19}{12}\approx 1.583333333$$

Solution Steps

Multiply 1 and 4 to get 4.

$$\frac{4+3}{4}+\frac{1}{6}-\frac{1}{3}$$

Add 4 and 3 to get 7.

$$\frac{7}{4}+\frac{1}{6}-\frac{1}{3}$$

Least common multiple of 4 and 6 is 12. Convert \frac{7}{4} and \frac{1}{6} to fractions with denominator 12.

$$\frac{21}{12}+\frac{2}{12}-\frac{1}{3}$$

Since \frac{21}{12} and \frac{2}{12} have the same denominator, add them by adding their numerators.

$$\frac{21+2}{12}-\frac{1}{3}$$

Add 21 and 2 to get 23.

$$\frac{23}{12}-\frac{1}{3}$$

Least common multiple of 12 and 3 is 12. Convert \frac{23}{12} and \frac{1}{3} to fractions with denominator 12.

$$\frac{23}{12}-\frac{4}{12}$$

Since \frac{23}{12} and \frac{4}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{23-4}{12}$$

Subtract 4 from 23 to get 19.

$$\frac{19}{12}$$

Factor

$$\frac{19}{2 ^ {2} \cdot 3} = 1\frac{7}{12} = 1.5833333333333333$$