Solve 13/10+14/5-11/4

$$1 \frac { 3 } { 10 } + 1 \frac { 4 } { 5 } - 1 \frac { 1 } { 4 }$$

Evaluate

$$\frac{37}{20}=1.85$$

Solution Steps

Multiply 1 and 10 to get 10.

$$\frac{10+3}{10}+\frac{1\times 5+4}{5}-\frac{1\times 4+1}{4}$$

Add 10 and 3 to get 13.

$$\frac{13}{10}+\frac{1\times 5+4}{5}-\frac{1\times 4+1}{4}$$

Multiply 1 and 5 to get 5.

$$\frac{13}{10}+\frac{5+4}{5}-\frac{1\times 4+1}{4}$$

Add 5 and 4 to get 9.

$$\frac{13}{10}+\frac{9}{5}-\frac{1\times 4+1}{4}$$

Least common multiple of 10 and 5 is 10. Convert \frac{13}{10} and \frac{9}{5} to fractions with denominator 10.

$$\frac{13}{10}+\frac{18}{10}-\frac{1\times 4+1}{4}$$

Since \frac{13}{10} and \frac{18}{10} have the same denominator, add them by adding their numerators.

$$\frac{13+18}{10}-\frac{1\times 4+1}{4}$$

Add 13 and 18 to get 31.

$$\frac{31}{10}-\frac{1\times 4+1}{4}$$

Multiply 1 and 4 to get 4.

$$\frac{31}{10}-\frac{4+1}{4}$$

Add 4 and 1 to get 5.

$$\frac{31}{10}-\frac{5}{4}$$

Least common multiple of 10 and 4 is 20. Convert \frac{31}{10} and \frac{5}{4} to fractions with denominator 20.

$$\frac{62}{20}-\frac{25}{20}$$

Since \frac{62}{20} and \frac{25}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{62-25}{20}$$

Subtract 25 from 62 to get 37.

$$\frac{37}{20}$$

Factor

$$\frac{37}{2 ^ {2} \cdot 5} = 1\frac{17}{20} = 1.85$$