Solve 128/y-9/x=1

$$1 \frac { 28 } { y } - \frac { 9 } { x } = 1$$

Solve for x

$$x=-\frac{9y}{y-28}$$

$$y\neq 0\text{ and }y\neq 28$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by xy, the least common multiple of y,x.

$$1x\times 28-y\times 9=xy$$

Multiply 1 and 28 to get 28.

$$28x-y\times 9=xy$$

Subtract xy from both sides.

$$28x-y\times 9-xy=0$$

Add y\times 9 to both sides. Anything plus zero gives itself.

$$28x-xy=y\times 9$$

Combine all terms containing x.

$$\left(28-y\right)x=y\times 9$$

The equation is in standard form.

$$\left(28-y\right)x=9y$$

Divide both sides by 28-y.

$$\frac{\left(28-y\right)x}{28-y}=\frac{9y}{28-y}$$

Dividing by 28-y undoes the multiplication by 28-y.

$$x=\frac{9y}{28-y}$$

Variable x cannot be equal to 0.

$$x=\frac{9y}{28-y}\text{, }x\neq 0$$

Solve for y

$$y=\frac{28x}{x+9}$$

$$x\neq 0\text{ and }x\neq -9$$

Steps for Solving Linear Equation

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by xy, the least common multiple of y,x.

$$1x\times 28-y\times 9=xy$$

Multiply 1 and 28 to get 28.

$$28x-y\times 9=xy$$

Subtract xy from both sides.

$$28x-y\times 9-xy=0$$

Subtract 28x from both sides. Anything subtracted from zero gives its negation.

$$-y\times 9-xy=-28x$$

Multiply -1 and 9 to get -9.

$$-9y-xy=-28x$$

Combine all terms containing y.

$$\left(-9-x\right)y=-28x$$

The equation is in standard form.

$$\left(-x-9\right)y=-28x$$

Divide both sides by -9-x.

$$\frac{\left(-x-9\right)y}{-x-9}=-\frac{28x}{-x-9}$$

Dividing by -9-x undoes the multiplication by -9-x.

$$y=-\frac{28x}{-x-9}$$

Divide -28x by -9-x.

$$y=\frac{28x}{x+9}$$

Variable y cannot be equal to 0.

$$y=\frac{28x}{x+9}\text{, }y\neq 0$$