Solve 122/49div240/30=

$$1 \frac { 22 } { 49 } \div 2 \frac { 40 } { 30 } =$$

Evaluate

$$\frac{213}{490}\approx 0.434693878$$

Solution Steps

Divide \frac{1\times 49+22}{49} by \frac{2\times 30+40}{30} by multiplying \frac{1\times 49+22}{49} by the reciprocal of \frac{2\times 30+40}{30}.

$$\frac{\left(1\times 49+22\right)\times 30}{49\left(2\times 30+40\right)}$$

Multiply 1 and 49 to get 49.

$$\frac{\left(49+22\right)\times 30}{49\left(2\times 30+40\right)}$$

Add 49 and 22 to get 71.

$$\frac{71\times 30}{49\left(2\times 30+40\right)}$$

Multiply 71 and 30 to get 2130.

$$\frac{2130}{49\left(2\times 30+40\right)}$$

Multiply 2 and 30 to get 60.

$$\frac{2130}{49\left(60+40\right)}$$

Add 60 and 40 to get 100.

$$\frac{2130}{49\times 100}$$

Multiply 49 and 100 to get 4900.

$$\frac{2130}{4900}$$

Reduce the fraction \frac{2130}{4900} to lowest terms by extracting and canceling out 10.

$$\frac{213}{490}$$

Factor

$$\frac{3 \cdot 71}{2 \cdot 5 \cdot 7 ^ {2}} = 0.4346938775510204$$