Solve 12/7*{6-(5-2/3*11/8)}

$$1 \frac { 2 } { 7 } \times \{ 6 - ( 5 - \frac { 2 } { 3 } \times 1 \frac { 1 } { 8 } ) \}$$

Evaluate

$$\frac{9}{4}=2.25$$

Solution Steps

Multiply 1 and 7 to get 7.

$$\frac{7+2}{7}\left(6-\left(5-\frac{2}{3}\times \frac{1\times 8+1}{8}\right)\right)$$

Add 7 and 2 to get 9.

$$\frac{9}{7}\left(6-\left(5-\frac{2}{3}\times \frac{1\times 8+1}{8}\right)\right)$$

Multiply 1 and 8 to get 8.

$$\frac{9}{7}\left(6-\left(5-\frac{2}{3}\times \frac{8+1}{8}\right)\right)$$

Add 8 and 1 to get 9.

$$\frac{9}{7}\left(6-\left(5-\frac{2}{3}\times \frac{9}{8}\right)\right)$$

Multiply \frac{2}{3} times \frac{9}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9}{7}\left(6-\left(5-\frac{2\times 9}{3\times 8}\right)\right)$$

Do the multiplications in the fraction \frac{2\times 9}{3\times 8}.

$$\frac{9}{7}\left(6-\left(5-\frac{18}{24}\right)\right)$$

Reduce the fraction \frac{18}{24} to lowest terms by extracting and canceling out 6.

$$\frac{9}{7}\left(6-\left(5-\frac{3}{4}\right)\right)$$

Convert 5 to fraction \frac{20}{4}.

$$\frac{9}{7}\left(6-\left(\frac{20}{4}-\frac{3}{4}\right)\right)$$

Since \frac{20}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9}{7}\left(6-\frac{20-3}{4}\right)$$

Subtract 3 from 20 to get 17.

$$\frac{9}{7}\left(6-\frac{17}{4}\right)$$

Convert 6 to fraction \frac{24}{4}.

$$\frac{9}{7}\left(\frac{24}{4}-\frac{17}{4}\right)$$

Since \frac{24}{4} and \frac{17}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9}{7}\times \frac{24-17}{4}$$

Subtract 17 from 24 to get 7.

$$\frac{9}{7}\times \frac{7}{4}$$

Multiply \frac{9}{7} times \frac{7}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 7}{7\times 4}$$

Cancel out 7 in both numerator and denominator.

$$\frac{9}{4}$$

Factor

$$\frac{3 ^ {2}}{2 ^ {2}} = 2\frac{1}{4} = 2.25$$