Solve 12/7+3+3/7

$$1 \frac { 2 } { 7 } + 3 + \frac { 3 } { 7 }$$

Evaluate

$$\frac{33}{7}\approx 4.714285714$$

Solution Steps

Multiply 1 and 7 to get 7.

$$\frac{7+2}{7}+3+\frac{3}{7}$$

Add 7 and 2 to get 9.

$$\frac{9}{7}+3+\frac{3}{7}$$

Convert 3 to fraction \frac{21}{7}.

$$\frac{9}{7}+\frac{21}{7}+\frac{3}{7}$$

Since \frac{9}{7} and \frac{21}{7} have the same denominator, add them by adding their numerators.

$$\frac{9+21}{7}+\frac{3}{7}$$

Add 9 and 21 to get 30.

$$\frac{30}{7}+\frac{3}{7}$$

Since \frac{30}{7} and \frac{3}{7} have the same denominator, add them by adding their numerators.

$$\frac{30+3}{7}$$

Add 30 and 3 to get 33.

$$\frac{33}{7}$$

Factor

$$\frac{3 \cdot 11}{7} = 4\frac{5}{7} = 4.714285714285714$$