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\frac{\left(1\times 5+2\right)\times 20}{5\left(1\times 20+1\right)}\times \frac{5}{7}
Divide \frac{1\times 5+2}{5} by \frac{1\times 20+1}{20} by multiplying \frac{1\times 5+2}{5} by the reciprocal of \frac{1\times 20+1}{20}.
\frac{4\left(2+5\right)}{1+20}\times \frac{5}{7}
Cancel out 5 in both numerator and denominator.
\frac{4\times 7}{1+20}\times \frac{5}{7}
Add 2 and 5 to get 7.
\frac{28}{1+20}\times \frac{5}{7}
Multiply 4 and 7 to get 28.
\frac{28}{21}\times \frac{5}{7}
Add 1 and 20 to get 21.
\frac{4}{3}\times \frac{5}{7}
Reduce the fraction \frac{28}{21} to lowest terms by extracting and canceling out 7.
\frac{4\times 5}{3\times 7}
Multiply \frac{4}{3} times \frac{5}{7} by multiplying numerator times numerator and denominator times denominator.
\frac{20}{21}
Do the multiplications in the fraction \frac{4\times 5}{3\times 7}.