Solve 12/5+7/8+13=

$$1 \frac { 2 } { 5 } + \frac { 7 } { 8 } + 13 =$$

Evaluate

$$\frac{611}{40}=15.275$$

Solution Steps

Multiply 1 and 5 to get 5.

$$\frac{5+2}{5}+\frac{7}{8}+13$$

Add 5 and 2 to get 7.

$$\frac{7}{5}+\frac{7}{8}+13$$

Least common multiple of 5 and 8 is 40. Convert \frac{7}{5} and \frac{7}{8} to fractions with denominator 40.

$$\frac{56}{40}+\frac{35}{40}+13$$

Since \frac{56}{40} and \frac{35}{40} have the same denominator, add them by adding their numerators.

$$\frac{56+35}{40}+13$$

Add 56 and 35 to get 91.

$$\frac{91}{40}+13$$

Convert 13 to fraction \frac{520}{40}.

$$\frac{91}{40}+\frac{520}{40}$$

Since \frac{91}{40} and \frac{520}{40} have the same denominator, add them by adding their numerators.

$$\frac{91+520}{40}$$

Add 91 and 520 to get 611.

$$\frac{611}{40}$$

Factor

$$\frac{13 \cdot 47}{2 ^ {3} \cdot 5} = 15\frac{11}{40} = 15.275$$