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\frac{\left(1\times 4+2\right)\times 3}{4\left(7\times 3+1\right)}
Divide \frac{1\times 4+2}{4} by \frac{7\times 3+1}{3} by multiplying \frac{1\times 4+2}{4} by the reciprocal of \frac{7\times 3+1}{3}.
\frac{\left(4+2\right)\times 3}{4\left(7\times 3+1\right)}
Multiply 1 and 4 to get 4.
\frac{6\times 3}{4\left(7\times 3+1\right)}
Add 4 and 2 to get 6.
\frac{18}{4\left(7\times 3+1\right)}
Multiply 6 and 3 to get 18.
\frac{18}{4\left(21+1\right)}
Multiply 7 and 3 to get 21.
\frac{18}{4\times 22}
Add 21 and 1 to get 22.
\frac{18}{88}
Multiply 4 and 22 to get 88.
\frac{9}{44}
Reduce the fraction \frac{18}{88} to lowest terms by extracting and canceling out 2.