Solve 12/4+31/7

$$1 \frac { 2 } { 4 } + 3 \frac { 1 } { 7 }$$

Evaluate

$$\frac{65}{14}\approx 4.642857143$$

Solution Steps

Multiply 1 and 4 to get 4.

$$\frac{4+2}{4}+\frac{3\times 7+1}{7}$$

Add 4 and 2 to get 6.

$$\frac{6}{4}+\frac{3\times 7+1}{7}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}+\frac{3\times 7+1}{7}$$

Multiply 3 and 7 to get 21.

$$\frac{3}{2}+\frac{21+1}{7}$$

Add 21 and 1 to get 22.

$$\frac{3}{2}+\frac{22}{7}$$

Least common multiple of 2 and 7 is 14. Convert \frac{3}{2} and \frac{22}{7} to fractions with denominator 14.

$$\frac{21}{14}+\frac{44}{14}$$

Since \frac{21}{14} and \frac{44}{14} have the same denominator, add them by adding their numerators.

$$\frac{21+44}{14}$$

Add 21 and 44 to get 65.

$$\frac{65}{14}$$

Factor

$$\frac{5 \cdot 13}{2 \cdot 7} = 4\frac{9}{14} = 4.642857142857143$$