Solve 12/4+11/3=

$$1 \frac { 2 } { 4 } + 1 \frac { 1 } { 3 } =$$

Evaluate

$$\frac{17}{6}\approx 2.833333333$$

Solution Steps

Multiply 1 and 4 to get 4.

$$\frac{4+2}{4}+\frac{1\times 3+1}{3}$$

Add 4 and 2 to get 6.

$$\frac{6}{4}+\frac{1\times 3+1}{3}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}+\frac{1\times 3+1}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{3}{2}+\frac{3+1}{3}$$

Add 3 and 1 to get 4.

$$\frac{3}{2}+\frac{4}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{3}{2} and \frac{4}{3} to fractions with denominator 6.

$$\frac{9}{6}+\frac{8}{6}$$

Since \frac{9}{6} and \frac{8}{6} have the same denominator, add them by adding their numerators.

$$\frac{9+8}{6}$$

Add 9 and 8 to get 17.

$$\frac{17}{6}$$

Factor

$$\frac{17}{2 \cdot 3} = 2\frac{5}{6} = 2.8333333333333335$$