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\frac{\left(1\times 3+2\right)\times 3}{3\left(1\times 3+1\right)}
Divide \frac{1\times 3+2}{3} by \frac{1\times 3+1}{3} by multiplying \frac{1\times 3+2}{3} by the reciprocal of \frac{1\times 3+1}{3}.
\frac{2+3}{1+3}
Cancel out 3 in both numerator and denominator.
\frac{5}{1+3}
Add 2 and 3 to get 5.
\frac{5}{4}
Add 1 and 3 to get 4.