Solve 12/3+41/4div15/12

$$1 \frac { 2 } { 3 } + 4 \frac { 1 } { 4 } \div 1 \frac { 5 } { 12 }$$

Evaluate

$$\frac{14}{3}\approx 4.666666667$$

Solution Steps

Multiply 1 and 3 to get 3.

$$\frac{3+2}{3}+\frac{\frac{4\times 4+1}{4}}{\frac{1\times 12+5}{12}}$$

Add 3 and 2 to get 5.

$$\frac{5}{3}+\frac{\frac{4\times 4+1}{4}}{\frac{1\times 12+5}{12}}$$

Divide \frac{4\times 4+1}{4} by \frac{1\times 12+5}{12} by multiplying \frac{4\times 4+1}{4} by the reciprocal of \frac{1\times 12+5}{12}.

$$\frac{5}{3}+\frac{\left(4\times 4+1\right)\times 12}{4\left(1\times 12+5\right)}$$

Cancel out 4 in both numerator and denominator.

$$\frac{5}{3}+\frac{3\left(1+4\times 4\right)}{5+12}$$

Multiply 4 and 4 to get 16.

$$\frac{5}{3}+\frac{3\left(1+16\right)}{5+12}$$

Add 1 and 16 to get 17.

$$\frac{5}{3}+\frac{3\times 17}{5+12}$$

Multiply 3 and 17 to get 51.

$$\frac{5}{3}+\frac{51}{5+12}$$

Add 5 and 12 to get 17.

$$\frac{5}{3}+\frac{51}{17}$$

Divide 51 by 17 to get 3.

$$\frac{5}{3}+3$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{5}{3}+\frac{9}{3}$$

Since \frac{5}{3} and \frac{9}{3} have the same denominator, add them by adding their numerators.

$$\frac{5+9}{3}$$

Add 5 and 9 to get 14.

$$\frac{14}{3}$$

Factor

$$\frac{2 \cdot 7}{3} = 4\frac{2}{3} = 4.666666666666667$$