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\frac{\left(1\times 2+2\right)\times \frac{4\times 4+1}{4}}{2\times \frac{1\times 2+1}{2}}
Divide \frac{1\times 2+2}{2} by \frac{\frac{1\times 2+1}{2}}{\frac{4\times 4+1}{4}} by multiplying \frac{1\times 2+2}{2} by the reciprocal of \frac{\frac{1\times 2+1}{2}}{\frac{4\times 4+1}{4}}.
\frac{\left(2+2\right)\times \frac{4\times 4+1}{4}}{2\times \frac{1\times 2+1}{2}}
Multiply 1 and 2 to get 2.
\frac{4\times \frac{4\times 4+1}{4}}{2\times \frac{1\times 2+1}{2}}
Add 2 and 2 to get 4.
\frac{4\times \frac{16+1}{4}}{2\times \frac{1\times 2+1}{2}}
Multiply 4 and 4 to get 16.
\frac{4\times \frac{17}{4}}{2\times \frac{1\times 2+1}{2}}
Add 16 and 1 to get 17.
\frac{17}{2\times \frac{1\times 2+1}{2}}
Cancel out 4 and 4.
\frac{17}{2\times \frac{2+1}{2}}
Multiply 1 and 2 to get 2.
\frac{17}{2\times \frac{3}{2}}
Add 2 and 1 to get 3.
\frac{17}{3}
Cancel out 2 and 2.