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\frac{\left(1\times 8+1\right)\times 10}{8}
Divide \frac{1\times 8+1}{8} by \frac{1}{10} by multiplying \frac{1\times 8+1}{8} by the reciprocal of \frac{1}{10}.
\frac{\left(8+1\right)\times 10}{8}
Multiply 1 and 8 to get 8.
\frac{9\times 10}{8}
Add 8 and 1 to get 9.
\frac{90}{8}
Multiply 9 and 10 to get 90.
\frac{45}{4}
Reduce the fraction \frac{90}{8} to lowest terms by extracting and canceling out 2.