Solve 11/8+53/20+65/10

$$1 \frac { 1 } { 8 } + 5 \frac { 3 } { 20 } + 6 \frac { 5 } { 10 }$$

Evaluate

$$\frac{511}{40}=12.775$$

Solution Steps

Multiply 1 and 8 to get 8.

$$\frac{8+1}{8}+\frac{5\times 20+3}{20}+\frac{6\times 10+5}{10}$$

Add 8 and 1 to get 9.

$$\frac{9}{8}+\frac{5\times 20+3}{20}+\frac{6\times 10+5}{10}$$

Multiply 5 and 20 to get 100.

$$\frac{9}{8}+\frac{100+3}{20}+\frac{6\times 10+5}{10}$$

Add 100 and 3 to get 103.

$$\frac{9}{8}+\frac{103}{20}+\frac{6\times 10+5}{10}$$

Least common multiple of 8 and 20 is 40. Convert \frac{9}{8} and \frac{103}{20} to fractions with denominator 40.

$$\frac{45}{40}+\frac{206}{40}+\frac{6\times 10+5}{10}$$

Since \frac{45}{40} and \frac{206}{40} have the same denominator, add them by adding their numerators.

$$\frac{45+206}{40}+\frac{6\times 10+5}{10}$$

Add 45 and 206 to get 251.

$$\frac{251}{40}+\frac{6\times 10+5}{10}$$

Multiply 6 and 10 to get 60.

$$\frac{251}{40}+\frac{60+5}{10}$$

Add 60 and 5 to get 65.

$$\frac{251}{40}+\frac{65}{10}$$

Reduce the fraction \frac{65}{10} to lowest terms by extracting and canceling out 5.

$$\frac{251}{40}+\frac{13}{2}$$

Least common multiple of 40 and 2 is 40. Convert \frac{251}{40} and \frac{13}{2} to fractions with denominator 40.

$$\frac{251}{40}+\frac{260}{40}$$

Since \frac{251}{40} and \frac{260}{40} have the same denominator, add them by adding their numerators.

$$\frac{251+260}{40}$$

Add 251 and 260 to get 511.

$$\frac{511}{40}$$

Factor

$$\frac{7 \cdot 73}{2 ^ {3} \cdot 5} = 12\frac{31}{40} = 12.775$$