Solve 11/6-22/3=

$$1 \frac { 1 } { 6 } - 2 \frac { 2 } { 3 } =$$

Evaluate

$$-\frac{3}{2}=-1.5$$

Solution Steps

Multiply 1 and 6 to get 6.

$$\frac{6+1}{6}-\frac{2\times 3+2}{3}$$

Add 6 and 1 to get 7.

$$\frac{7}{6}-\frac{2\times 3+2}{3}$$

Multiply 2 and 3 to get 6.

$$\frac{7}{6}-\frac{6+2}{3}$$

Add 6 and 2 to get 8.

$$\frac{7}{6}-\frac{8}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{7}{6} and \frac{8}{3} to fractions with denominator 6.

$$\frac{7}{6}-\frac{16}{6}$$

Since \frac{7}{6} and \frac{16}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-16}{6}$$

Subtract 16 from 7 to get -9.

$$\frac{-9}{6}$$

Reduce the fraction \frac{-9}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{3}{2}$$

Factor

$$-\frac{3}{2} = -1\frac{1}{2} = -1.5$$