Solve 11/6+(-25/8)=

$$1 \frac { 1 } { 6 } + ( - 2 \frac { 5 } { 8 } ) =$$

Evaluate

$$-\frac{35}{24}\approx -1.458333333$$

Solution Steps

Multiply 1 and 6 to get 6.

$$\frac{6+1}{6}-\frac{2\times 8+5}{8}$$

Add 6 and 1 to get 7.

$$\frac{7}{6}-\frac{2\times 8+5}{8}$$

Multiply 2 and 8 to get 16.

$$\frac{7}{6}-\frac{16+5}{8}$$

Add 16 and 5 to get 21.

$$\frac{7}{6}-\frac{21}{8}$$

Least common multiple of 6 and 8 is 24. Convert \frac{7}{6} and \frac{21}{8} to fractions with denominator 24.

$$\frac{28}{24}-\frac{63}{24}$$

Since \frac{28}{24} and \frac{63}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-63}{24}$$

Subtract 63 from 28 to get -35.

$$-\frac{35}{24}$$

Factor

$$-\frac{35}{24} = -1\frac{11}{24} = -1.4583333333333333$$