Solve 11/6+7/8=

$$1 \frac { 1 } { 6 } + \frac { 7 } { 8 } =$$

Evaluate

$$\frac{49}{24}\approx 2.041666667$$

Solution Steps

Multiply 1 and 6 to get 6.

$$\frac{6+1}{6}+\frac{7}{8}$$

Add 6 and 1 to get 7.

$$\frac{7}{6}+\frac{7}{8}$$

Least common multiple of 6 and 8 is 24. Convert \frac{7}{6} and \frac{7}{8} to fractions with denominator 24.

$$\frac{28}{24}+\frac{21}{24}$$

Since \frac{28}{24} and \frac{21}{24} have the same denominator, add them by adding their numerators.

$$\frac{28+21}{24}$$

Add 28 and 21 to get 49.

$$\frac{49}{24}$$

Factor

$$\frac{7 ^ {2}}{2 ^ {3} \cdot 3} = 2\frac{1}{24} = 2.0416666666666665$$