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\frac{\left(1\times 35+1\right)\times 63}{35\times 20}
Divide \frac{1\times 35+1}{35} by \frac{20}{63} by multiplying \frac{1\times 35+1}{35} by the reciprocal of \frac{20}{63}.
\frac{9\left(1+35\right)}{5\times 20}
Cancel out 7 in both numerator and denominator.
\frac{9\times 36}{5\times 20}
Add 1 and 35 to get 36.
\frac{324}{5\times 20}
Multiply 9 and 36 to get 324.
\frac{324}{100}
Multiply 5 and 20 to get 100.
\frac{81}{25}
Reduce the fraction \frac{324}{100} to lowest terms by extracting and canceling out 4.