Solve 11/3-7/12+Delta-11/30+13/42-frac{15}{56}=frac{7}{8}

$$1 \frac { 1 } { 3 } - \frac { 7 } { 12 } + \Delta - \frac { 11 } { 30 } + \frac { 13 } { 42 } - \frac { 15 } { 56 } = \frac { 7 } { 8 }$$

Solve for Δ

$$\Delta =\frac{9}{20}=0.45$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 840, the least common multiple of 3,12,30,42,56,8.

$$280\left(1\times 3+1\right)-490+840\Delta -308+260-225=735$$

Multiply 1 and 3 to get 3.

$$280\left(3+1\right)-490+840\Delta -308+260-225=735$$

Add 3 and 1 to get 4.

$$280\times 4-490+840\Delta -308+260-225=735$$

Multiply 280 and 4 to get 1120.

$$1120-490+840\Delta -308+260-225=735$$

Subtract 490 from 1120 to get 630.

$$630+840\Delta -308+260-225=735$$

Subtract 308 from 630 to get 322.

$$322+840\Delta +260-225=735$$

Add 322 and 260 to get 582.

$$582+840\Delta -225=735$$

Subtract 225 from 582 to get 357.

$$357+840\Delta =735$$

Subtract 357 from both sides.

$$840\Delta =735-357$$

Subtract 357 from 735 to get 378.

$$840\Delta =378$$

Divide both sides by 840.

$$\Delta =\frac{378}{840}$$

Reduce the fraction \frac{378}{840} to lowest terms by extracting and canceling out 42.

$$\Delta =\frac{9}{20}$$