Solve 11/3-2/9+1,6

$$1 \frac { 1 } { 3 } - \frac { 2 } { 9 } + 1,6$$

Evaluate

$$\frac{122}{45}\approx 2,711111111$$

Solution Steps

Multiply 1 and 3 to get 3.

$$\frac{3+1}{3}-\frac{2}{9}+1,6$$

Add 3 and 1 to get 4.

$$\frac{4}{3}-\frac{2}{9}+1,6$$

Least common multiple of 3 and 9 is 9. Convert \frac{4}{3} and \frac{2}{9} to fractions with denominator 9.

$$\frac{12}{9}-\frac{2}{9}+1,6$$

Since \frac{12}{9} and \frac{2}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-2}{9}+1,6$$

Subtract 2 from 12 to get 10.

$$\frac{10}{9}+1,6$$

Convert decimal number 1,6 to fraction \frac{16}{10}. Reduce the fraction \frac{16}{10} to lowest terms by extracting and canceling out 2.

$$\frac{10}{9}+\frac{8}{5}$$

Least common multiple of 9 and 5 is 45. Convert \frac{10}{9} and \frac{8}{5} to fractions with denominator 45.

$$\frac{50}{45}+\frac{72}{45}$$

Since \frac{50}{45} and \frac{72}{45} have the same denominator, add them by adding their numerators.

$$\frac{50+72}{45}$$

Add 50 and 72 to get 122.

$$\frac{122}{45}$$

Factor

$$\frac{2 \cdot 61}{5 \cdot 3 ^ {2}} = 2\frac{32}{45} = 2.7111111111111112$$