Solve 11/3div22/9=

$$1 \frac { 1 } { 3 } \div 2 \frac { 2 } { 9 } =$$

Evaluate

$$\frac{3}{5}=0.6$$

Solution Steps

Divide \frac{1\times 3+1}{3} by \frac{2\times 9+2}{9} by multiplying \frac{1\times 3+1}{3} by the reciprocal of \frac{2\times 9+2}{9}.

$$\frac{\left(1\times 3+1\right)\times 9}{3\left(2\times 9+2\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{3\left(1+3\right)}{2+2\times 9}$$

Add 1 and 3 to get 4.

$$\frac{3\times 4}{2+2\times 9}$$

Multiply 3 and 4 to get 12.

$$\frac{12}{2+2\times 9}$$

Multiply 2 and 9 to get 18.

$$\frac{12}{2+18}$$

Add 2 and 18 to get 20.

$$\frac{12}{20}$$

Reduce the fraction \frac{12}{20} to lowest terms by extracting and canceling out 4.

$$\frac{3}{5}$$

Factor

$$\frac{3}{5} = 0.6$$